-16x^2+255x-0=0

Solution for -16x^2+255x-0=0 equation:

-16x^2+255x-0=0

We add all the numbers together, and all the variables

-16x^2+255x=0

a = -16; b = 255; c = 0;
Δ = b2-4ac
Δ = 2552-4·(-16)·0
Δ = 65025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65025}=255$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(255)-255}{2*-16}=\frac{-510}{-32}
=15+15/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(255)+255}{2*-16}=\frac{0}{-32}
=0
$